The determinant of a triangular matrix is just the product of the diagonal entries. Notice that we swapped two rows, thus we multiply the product by (−1).
detA=(−1)⋅1⋅1⋅1⋅10
True or False: If detA is zero, then two rows or two columns are the same, or a row or a column is zero.
False. By Invertible Matrix Theorem, detA=0 implies linear dependence. However, this isn't the correct definition.
True or False: detA−1=(−1)detA
False. Most obvious counter-example is the identity matrix I, which serves as its own inverse
detI−1=detI
3.3 Cramer's Rule, Volume, and Linear Transformations
Theorem 7: Cramer’s Rule
Let A be an invertible n×n matrix. For any b in Rn, the unique solution x of Ax=b has entries given by
xi=detAdetAi(b)
where Ai(b) is A with the i-th column replaced with b.
If A is a 2×2 matrix, the area of the parallelogram determined by the columns of A is ∣detA∣. This extends to 3 dimensional volume of parallelepipeds. Note that one of the vectors must be at the origin.
Example: Calculate the area of the parallelogram determined by the points (−2,−2),(0,3),(4,−1),(6,4)
First, we must transpose the shape such that one of the points is at the origin. So we transpose the whole shape by (0,−3).
(−2,−5),(0,0),(4,−4),(6,1)
Then, choose any 2 points non-origin vectors that are not on the same y-coordinate to be the defining vectors and compute the determinant.
Determine the values of the parameter s for which the system has a unique solution, describe the solution.
By Invertible Matrix Theorem and Theorem 4, we know that a matrix is invertible if and only if detA=0. We know the determinant is given by detA=15s2−60, which has the roots ±2. Using Cramer’s rule, we can express the general solution to the system:
And we create the adjugate matrix in transpose order:
adjA=63−660−3−5−12
Find the area of the parallelogram defined by the following vertices: (0,−2)(5,−2),(−3,1),(2,1)
By Theorem 9, we know that the area of this parallelogram is given by the determinant of any two non-origin vectors. First, we transpose the shape to the origin, translating by (0,2).
(0,0)(5,0),(−3,3),(2,3)
Then select any 2 non-origin vectors that are not on the same y-coordinate and compute their determinant:
50−33=5023=15
Note that the following two vectors do not work because they share the same y-coordinate:
−3323=−15
Let T:Rm→Rnbe a linear transformation, and let p be a vector and S a set in Rm. Show that the image of p+S under Tis the translated set T(p)+T(S) in Rn.
By definition, p+S is the set of all vectors of the form p+v. We know that linear transformations are closed under vector addition
T(p+v)=T(p)+T(v)
Thus, the above condition holds for each v∈S.
T(p+S)=T(p)+T(S)
Compute the area of the image of S under the mapping x↦Ax
A=[5121],b1=[4−7],b2=[01]
By Theorem 10 we know that the change in volume after the transformation by A is equal to the determinant of A.